768=-16t^2+224t+0

Solution for 768=-16t^2+224t+0 equation:

768=-16t^2+224t+0

We move all terms to the left:

768-(-16t^2+224t+0)=0

We get rid of parentheses

16t^2-224t-0+768=0

We add all the numbers together, and all the variables

16t^2-224t+768=0

a = 16; b = -224; c = +768;
Δ = b2-4ac
Δ = -2242-4·16·768
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-224)-32}{2*16}=\frac{192}{32}
=6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-224)+32}{2*16}=\frac{256}{32}
=8
$